A die is thrown once. What is the probability of getting a number lying between 11 and 55 ?


Answer:

1212

Step by Step Explanation:
  1. We know that in a single throw of a die we can get 1,2,3,4,5,1,2,3,4,5, or 6.6.
    So, the total number of possible outcomes =66.
  2. Let EE be an event of getting a number lying between 11 and 55.
    The event EE will happen when the number on the die is 2,3,2,3, or 44.
    Thus, the number of favorable outcomes = 33.
  3. We know that the probability of occurrence of an event EE, denoted by P(E)P(E) is defined as P(E)= Number of favorable outcomes  Total number of possible outcomes P(E)= Number of favorable outcomes  Total number of possible outcomes 
  4. Therefore, P( getting a number lying betweeen 1 and 5)=P(E)=36=12P( getting a number lying betweeen 1 and 5)=P(E)=36=12

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